Answer:
The circumference is [tex]C=12\sqrt{\pi }\:in[/tex].
Step-by-step explanation:
The area of a circle when we know the circumference is
[tex]A=\frac{C^2}{4\pi }[/tex]
We know the area [tex]A=36 \:{in^2}[/tex], we plug this value into the above equation and we solve for C the circumference.
[tex]36=\frac{C^2}{4\pi }\\\frac{C^2}{4\pi }=36\\\frac{C^2\cdot \:4\pi }{4\pi }=36\cdot \:4\pi \\\\C^2=144\pi \\C=\sqrt{144\pi }\\C=12\sqrt{\pi }[/tex]
The circumference is [tex]C=12\sqrt{\pi }\:in[/tex].
