Respuesta :
Since we have two points (2,54) and (4,54), we can assume a linear function and solve for the slope and intercept. So if V=kt+b where t is time passed and v is velocity of the car, we can plug in and solve for k and t, that would give t as a function of v, and you can graph it
t = time
v = velocity
you have (2,54) & (4,58)
v-54 = (58-54) / (4-2) *(t-2)
v=4/2(t-2)+54
v =2(t-2)+54
v = 2t-4+54
b - Graph by plotting the given points (2,54) & 4,58) and drawing a straight line through them