Respuesta :
In this question we simple wish to calculate the standard error and margin of error from the population. This can be done purely using the standard deviation and sample size.
Standard error
= std dev / (SQRT) n
= 11.5 / SQRT of 70
= 11.5 / 8.366
= 1.374
Margin of error is the standard error multiplied by a Z value that correspondence to a confidence percentage. At a 95% confidence the Z value is 1.96. Therefore
MOE = 1.96 x 1.374 = 2.69
Standard error
= std dev / (SQRT) n
= 11.5 / SQRT of 70
= 11.5 / 8.366
= 1.374
Margin of error is the standard error multiplied by a Z value that correspondence to a confidence percentage. At a 95% confidence the Z value is 1.96. Therefore
MOE = 1.96 x 1.374 = 2.69
The standard error of the mean for a sample of 70 students is 1.375 .
The margin of error of the mean is 2.69 .
[Round off your answers to the nearest hundredth]