Respuesta :
you can recall that
f(x-c) is shifting to the right by c units
f(x+c) is shifting to the left by c units
f(x)+c is shifting up by c units
f(x)-c is shifting down by c units
given that f(x)=1/x
g(x)=f(x+4)-6 thus f(x) is shifted to the left 4 units and down 6 units
f(x-c) is shifting to the right by c units
f(x+c) is shifting to the left by c units
f(x)+c is shifting up by c units
f(x)-c is shifting down by c units
given that f(x)=1/x
g(x)=f(x+4)-6 thus f(x) is shifted to the left 4 units and down 6 units
Answer with explanation:
We are given a parent function f(x) as:
[tex]f(x)=\dfrac{1}{x}[/tex]
and the transformed function g(x) is given by:
[tex]g(x)=\dfrac{1}{x+4}-6[/tex]
We know that the transformation of the type:
f(x) → f(x+a)
is either a shift a units to the left or to the right depending whether a is positive or negative respectively.
Also, the transformation of the type:
f(x) → f(x)+a
is the shift of the function f(x) either upward or downward depending on whether x is positive or negative respectively.
Here the function g(x) is:
[tex]g(x)=f(x+4)-6[/tex]
This means that the function g(x) is a shift of the function f(x) 4 units to the left and then it is translated 6 units downward.
Also we may see by the graph.