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What is the equation of a line that passes through the point (5, −4) and is parallel to the line whose equation is 2x + 5y = 10?

Respuesta :

choixongdong
2x + 5y = 10
5y = -2x + 10
  y = -2/5 x + 2
so slope = -2/5

passes through the point (5, −4)
y = mx + b
b = y - mx
b = -4 - (-2/5)(5)
b = -4 + 2
b = -2

equation
y = -2/5 x - 2

hope it helps

Answer:

y = -2/5 x - 2

Step-by-step explanation:

2x + 5y = 10

5y = -2x + 10

 y = -2/5 x + 2

so slope = -2/5

passes through the point (5, −4)

y = mx + b

b = y - mx

b = -4 - (-2/5)(5)

b = -4 + 2

b = -2

equation

y = -2/5 x - 2

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