Respuesta :

[tex]\bf \begin{cases} g(x)=x-3\\ h(x)=\sqrt{x}\\ (g\circ h)(x)=g(~~h(x)~~)\\ (g\circ h)(25)=g(~~h(25)~~) \end{cases} \\\\\\ h(25)=\sqrt{(25)}\implies \boxed{h(25)=5} \\\\\\ (g\circ h)(25)\implies g(~~h(25)~~)\implies g\left(~~\boxed{5}~~ \right)=(5)-3\implies g(5)=2[/tex]
The 'o' notation means function composition. In this case
(g o h)(x) = g(h(x))

The inner function h(x) goes first. Replace x with 25 and simplify to get
h(x) = sqrt(x)
h(25) = sqrt(25)
h(25) = 5

Therefore, 
(g o h)(25) = g(h(25)) = g(5)

Now we compute g(5)

g(x) = x-3
g(5) = 5-3
g(5) = 2

The answer is 2

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