Fred can mow a lawn in 60 minutes. Bullwinkle can mow the same lawn in 90 minutes. How long does it take for both Fred and Bullwinkle to mow the lawn if they are working together?

Let x=time required to mow the lawn if both work together

Then both work at the rate of 1/x lawn per min
fred works at the rate of 1/60 x

Bullwinkle at the rate of 1/90 x

1/60 + 1/90 = 3/180 + 2/180 = 5/180 = 1/36

rate of 1/x lawn per min so 1/36 =1/x

x= 36 min

fred mow 1/60 x = 1/60x36 =36/60= 9/15 of the lawn

Bullwinkle mow 1/90 x 36 = 36/90 = 6/15 of the lawn

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okpalawalter8 okpalawalter8 · Answer 2 · 2021-10-21T10:29:57+02:00

We have that for the Question "Fred can mow a lawn in 60 minutes. U can mow the same lawn in 90 minutes. How long does it take for both Fred and Bullwinkle to mow the lawn if they are working together?" it can be said thattime take for both Fred and Bullwinkle to mow the lawn if they are working together is

x=36 min

From the question we are told

Fred can mow a lawn in 60 minutes. U can mow the same lawn in 90 minutes. How long does it take for both Fred and Bullwinkle to mow the lawn if they are working together?

Generally the equation for the statements is mathematically given as

[tex]x=60\\\\y=90\\\\Therefore\\\\1/x=\frac{1}{90} + \frac{1}{60} \\\\1/x=\frac{1}{360} + \frac{6}{360}\\\\[/tex]

x=36 min

Therefore

time take for both Fred and Bullwinkle to mow the lawn if they are working together is

x=36 min

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