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Two balloons having the same charge of 1.2 × 10-6 coulombs each are kept 5.0 × 10-1 meters apart. What is the magnitude of the repulsive force between them? (k = 9.0 × 109 newton·meter2/coulombs2)

Respuesta :

coochicans
The answer is 5.2 × 10-2 newtons.

You need to use Coulomb's Law:


Q1= Q2 = 1.2 × 10 to the 6 C²
r = 5.0 × 10 to the 1 C²
k = 5.0 × 10 to the 9n*mto the second/c to the second.



 

The magnitude of the repulsive force between the two balloons is 5.2 × 10-2 newtons.

What is electrostatic force?

The electrostatic force F between two charged objects placed distance apart is directly proportional to the product of the magnitude of charges and inversely proportional to the square of the distance between them.

F = kq₁q₂/r²

where k = 9 x 10⁹ N.m²/C²

Given is the charge q₁ =q₂ =q =1.2 × 10⁻⁶ C,   distance r =0.5m

Substitute the values, we get the force F as

F = 9 x 10⁹x(1.2 × 10⁻⁶) ² / (0.5)²

F =  5.2 × 10⁻² N.

Thus, the  magnitude of the repulsive force is 5.2 × 10⁻² N.

Learn more about electrostatic force.

brainly.com/question/9774180

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