Mercury-203 undergoes beta minus decay. The subscript in the nuclide notation, Hg, is _____.
203 (?) Hg →?

The element symbol produced is _____.
It has a mass number _____.
and an atomic number _____.

203 (80) Hg → 203 (81) TI + ?

Mercury203 undergoes beta minus decay The subscript in the nuclide notation Hg is 203 Hg The element symbol produced is It has a mass number and an atomic numbe class=

Respuesta :

1. The subscript when writing the notation is always dedicated to the atomic number of the element. Since the atomic number for Mercury, Hg, is 80, then the subscript is 80.

2. For the second problem, you just have to balance out the subscripts and superscripts of the reactions.

Superscripts: 203 = 203 + ?; To balance, the missing number would be 0.
Subscripts: 80 = 81 + ?; To balance, the missing number would be -1.
Hence the particle produced is actually an electron, or a beta particle (not an element). The mass number is 0, and the atomic number is 0 (since it does not contain any proton).

Electron is the produced element having the symbol e, its mass number is zero and atomic number is -1.

What is beta minus reaction?

It is type of nuclear reaction in which a beta particle or an electron with no mass is ejected.

In the question subscript of Hg is asked, and in the place of subscript atomic number will come and the atomic number of mercury is 80. It will be notated as [tex]\[{}_{{\rm{80}}}^{{\rm{203}}}{\rm{Hg}}\][/tex].

As in the superscript masses are written and in the subscript atomic number is written and no. of superscript and subscript is always equal on both the sides. We know that in this decay an electron will emit, so the symbol of the produced element is e. And equation can be written as:

[tex]\[{}_{{\rm{80}}}^{{\rm{203}}}{\rm{Hg}} \to {}_{{\rm{81}}}^{{\rm{203}}}{\rm{Hg + }}{}_{\rm{x}}^{\rm{y}}{\rm{e}}\][/tex]

Calculation for the superscript:

As we know that in the superscript masses are written, so the mass of electron is y and it has value of 0, which can be calculated as follow-

203 = 203 + y

y = 0.

Calculation for the subscript:

As we know that in the subscript atomic number are written, so the atomic number of electron is x and it has value of -1, which can be calculated as follow-

80 = 81 + x

x = 80 - 81 = -1

Hence, the element symbol produced is electron, has a mass number zero and an atomic number -1.

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