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An apprentice jeweler determines the density of a sample of pure gold to be 20.3 g/cm3. the accepted value is 19.3 g/cm3. what is the percent error of the jeweler's density measurement?

Respuesta :

meerkat18
We are tasked to find the percent error of the jeweler's density measurement through the formula:

%Error= Absolute Value(Experimental Value - Theoretical value) x 100%/ Theoretical Value

We are given by the problem,
Experimental Value=20.3 g/cm3
Theoretical Value= 19.3 g/cm3
By Substituting the details,
%Error= Absolute Value(20.3 g/cm3 - 19.3 g/cm3) x 100% / 19.3 g/cm3
%Error=Absolute Value (1)/19.3
%Error= 100/19.3
%Error= 5.18%

Therefore, 5.18% is the percent error committed by the jeweler
Kalahira
accepted value - experimental value / accepted value * 100 = percent error (19.3 g/cm3 - 20.3 g/cm3) / (19.3 g/cm3) * 100% = 5.18 g/cm3

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