Respuesta :
Por definicion tenemos que
(F/A) = E(∆/0)
Sustituyendo los valores tenemos y despejando ∆:
∆ = (F/(πr2 × E))*0
(5000×5)/(3.14×(34×10^−2)^2×(125×10^8))
5.5×10^−6 m
(F/A) = E(∆/0)
Sustituyendo los valores tenemos y despejando ∆:
∆ = (F/(πr2 × E))*0
(5000×5)/(3.14×(34×10^−2)^2×(125×10^8))
5.5×10^−6 m
Answer:
The elongation will be 5.51 × 10^-4 m.
Explanation:
Force = F = 5000 N
Length = l = 5.0 m
Area = A = πr^2 = (3.14)(34 × 10^-3)^2 = 3.63 × 10^-3 m^2
Young’s Modulus = E = 125 × 10^8 N/m2
We know that:
E = (F/A)/(∆l/l)
∆l = (F l)/AE
∆l=(5000 ×5)/(3.63 × 10^(-3))( 125 × 10^8)
∆l = 5.51 × 10^-4 m