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Willchemistry
Hey there!:

Molar mass H3PO4 = 97.9952 g/mol

Atomic Masses :

H = 1.00794 a.m.u

P = 30.973762 a.m.u

O =  15.9994 a.m.u

H % =  [ ( 1.00794 * 3 ) /  97.9952  ]  * 100

H% = 3.0857 %

P % = [ ( 30.973762 * 1 ) / 97.9952 ] * 100

P% = 31.6074 %

O % = [ ( 15.9994 * 4 ) / 97.9952 ] * 100

O% = 65.3069 %


Hope this helps!

The percent composition has been calculated as the mass of the element in the compound.

The molecular mass of phosphoric acid = 97.9952 g/mol.

  • The percent composition of Hydrogen:

= [tex]\rm \dfrac{molecular\;mass\;\times\;number\;of\;atoms}{mass\;of\;H_3PO_4}\;\times\;100[/tex]

= [tex]\rm \dfrac{1\;\times\;3}{97.99}\;\times\;100[/tex]

= 3.085 %

  • The percent composition of Phosphorus:

= [tex]\rm \dfrac{16\;\times\;1}{97.99}\;\times\;100[/tex]

= 31.60 %

  • The percent composition of Oxygen:

= [tex]\rm \dfrac{32\;\times\;4}{97.99}\;\times\;100[/tex]

= 65.30 %

The percent composition of hydrogen is 3.085 %, phosphorus is 31.60 %, and oxygen is 65.30 %.

For more information about percent composition, refer to the link:

https://brainly.com/question/17505281

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