Respuesta :

Kalahira
0.11 M
   I am assuming that the 0.85% is by weight. So let's start with determining the molar mass of sodium hypochlorite (NaClO).
 Atomic weight sodium = 22.989769
 Atomic weight chlorine = 35.453
 Atomic weight oxygen = 15.999

   Molar mass NaClO = 22.989769 + 35.453 + 15.999 = 74.442 g/mol

   Now 1 liter of the solution will contain 1000 g * 0.0085 = 8.5 g.
 Moles NaClO = 8.5 g / 74.442 g/mol = 0.114182854 mol

   And since molarity is defined as moles per liter, the result (rounded to 2 significant digits) is 0.11 M
pstnonsonjoku

The molar concentration of the solution 0.114 M.

We can obtain the molar concentration from the weight percent of solution using the formula;

CM = 10 C%w/w d/MM

Where;

CM = molar concentration

C%w/w = percent concentration

d = density

MM = molar mass

Substituting values, we have;

CM = 10 × 0.85 × 1.0 /74.44

CM = 0.114 M

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