Respuesta :
Answer is: major product for the dehydration of 2-pentanol are 1-pentene (CH₂=CH-CH₂-CH₂-CH₃) and 2-pentene (CH₃-CH=CH-CH₂-CH₃) and water.
Adding hot, concentrated sulfuric acid to a secondary alkanol eliminates a water molecule from the organic molecule in a dehydration reaction.
2-pentanol, CH₃-CH₂-CH₂-CHOH-CH₃ s an unsymmetrical secondary alcohol.
Adding hot, concentrated sulfuric acid to a secondary alkanol eliminates a water molecule from the organic molecule in a dehydration reaction.
2-pentanol, CH₃-CH₂-CH₂-CHOH-CH₃ s an unsymmetrical secondary alcohol.
The removal of the water from the compound during the reaction is called dehydration.
The reagent used for the dehydration of the alcohol is as follows:-
- Concentrated sulfuric acid
- Concentrated phosphoric
The dehydration products of the 2- pentanol are as follows:-
- 1 pentene
- 2 pentene
The structure of the 1 pentene is (CH₂=CH-CH₂-CH₂-CH₃) and the structure of the 2 pentene is (CH₃-CH=CH-CH₂-CH₃).
The single bond represents the sigma bond and the double bond represents Pi bond.
For more information, refer to the link:-
https://brainly.com/question/4518679