The linear equation that could represent the image of the given straight line is 3x-4y=9.
The equation of the line is:
4y=3x+7
The mirror image of a line about origin will be obtained by replacing x with -x and y with -y.
The mirror image of the given line will be:
4(-y) = 3(-x) +7
3x-4y =7
When line 3x-4y =7 is dilated by any scale factor the resulted line will be parallel to 3x-4y =7.
So, the equation of the dilated line will be 3x-4y =k type.
Therefore, the linear equation that could represent the image of the given straight line is 3x-4y=9.
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