Respuesta :
Let the smaller number be x.
Given, the larger number is 7 times the smaller number.
So, the larger number = 7x.
Given, 3 times the larger number is 7 more than 4 times the smaller number.
So we can write the equation as,
[tex] 3(7x) = 4(x)+7 [/tex]
[tex] 3(7x) = 4x+7 [/tex]
[tex] 21x = 4x+7 [/tex]
Now we have to move 4x to the left side by subtracting 4x from both sides.
[tex] 21x-4x = 4x-4x+7 [/tex]
[tex] 21x-4x = 7 [/tex]
[tex] 17x = 7 [/tex]
To get x, we will divide both sides by 17. We will get,
[tex] \frac{17x}{17} = \frac{7}{17} [/tex]
[tex] x = \frac{7}{17} [/tex]
So the smaller number = [tex] \frac{7}{17} [/tex]
The larger number = [tex] 7(\frac{7}{17} ) [/tex] = [tex] \frac{49}{17} [/tex]
So we have got the required numbers.
Smaller number = [tex] \frac{7}{17} [/tex] and larger number = [tex] \frac{49}{17} [/tex].
Answer:
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Step-by-step explanation:
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