During this reaction, p4 + 5o2 → p4o10, 0.800 moles of product was made in 15.0 seconds. what is the rate of reaction? 56.8 g/min 227 g/min 908 g/min 13,600 g/min
The solution for this problem would be: The mass of P4O10 is computed by: 0.800 mol x 284 g/mol = 227g t = 15.0 s ( 1 min / 60 s) = 0.25 min So solving for the rate will be mass over t = m/t = 227/0.25 = 908 g/min would be the answer for this problem.
