[tex] 1 \frac{1}{4} [/tex] inch button = [tex] \frac{(1)(4)+1}{4} [/tex] inch = [tex] \frac{4+1}{4} [/tex] inch = [tex] \frac{5}{4} [/tex] inch
Given [tex] \frac{5}{4} [/tex] inch button and [tex] \frac{3}{8} [/tex] inch button. We have to find difference between them.
The difference between them is
[tex] \frac{5}{4} - \frac{3}{8} [/tex]
To subtract them first we have to make the denominators equal. As the denominators are 4 and 8 and 8 is multiple of 4. So we can take the common denominator as 8. To make the denominator of first fraction as 8, we will multiply the numerator and denominator of first fraction by 2. We will get,
[tex] \frac{(5)(2)}{(4)(2)} - \frac{3}{8} [/tex]
[tex] \frac{(5)(2)}{8} - \frac{3}{8} [/tex]
[tex] \frac{10}{8} - \frac{3}{8} [/tex]
Now as the denominator is same, we can subtract the numerator.
[tex] \frac{(10-3)}{8} [/tex]
[tex] \frac{7}{8} [/tex]
We have got the required answer.
The required difference of length between the buttons is [tex] \frac{7}{8} [/tex] inch.
