I believe the answer is (-2,-1) after the original point (2,1) goes through the change of -y,x
Answer:
Option B is correct.
The coordinate of A' is (-2 , -1)
Explanation:
The coordinates of ABCD are A = (-1,2) , B(1,1) , C =(1,-1) and D(-2,-2).
Rotation means moving the shape around a fixed point clockwise or anticlockwise, and by a certain number of degrees.
Rule for 90° counterclockwise rotation about the origin: [tex](x,y) \rightarrow (-y,x)[/tex]
or we can say that switch x and y in the coordinates and make y value opposite.
Then, the coordinate of A' :
[tex]A(-1,2) \rightarrow A'(-2 ,-1) [/tex]
Therefore, the coordinate of A' in the quadrilateral A'B'C'D' is, (-2 ,-1)