In order to find which one of the given points is a solution to the equation, we need to plug each point in the equation and check which one fits in .
The equation is :
5x+2y=-9
a.(2,-4)
5x+2y=-9
LHS: 5x+2y
Plugging (2,-4) in this,
5(2) +2(-4) = 10-8 =2
RHS : -9
LHS ≠RHS
So (2,-4) is not the solution.
b.(-1,2)
5x+2y=-9
LHS: 5x+2y
Plugging (-1,2) in this,
5(-1) +2(2) = -5+4 =-1
RHS : -9
LHS ≠RHS
So (-1,2) is not the solution.
c.(-2,5)
5x+2y=-9
LHS: 5x+2y
Plugging (-2,5) in this,
5(-2) +2(5) = -10+10 =0
RHS : -9
LHS ≠RHS
So (-2,5) is not the solution.
d.(1,-3)
5x+2y=-9
LHS: 5x+2y
Plugging (1,-3) in this,
5(1) +2(-3) = 5-6=-1
RHS : -9
LHS ≠RHS
So (1,-3) is not the solution.
None of the given options is a solution to the given equation.
