contestada

If a current of 0.5 A flows in a 75 W light bulb when the voltage difference between the ends of the filament is 150 V, what is the resistance of the filament?

Respuesta :

Power is current times voltage.  Using Ohm's Law V=IR, we can express power in two additional ways:
[tex]P=I^2R \\ P= \frac{V^2}{R} [/tex]
So for P=75W, we can use either of these to get R.  Let's use the first one:
[tex]75W=(0.5A)^2R \\ \frac{75W}{0.25A^2}=300 \Omega [/tex]

Answer:

300 would be the best anwer.

Explanation: