Respuesta :
Exponential functions are related to logarithmic functions in that they are inverse functions. Exponential functions move quickly up towards a [y] infinity, bounded by a vertical asymptote (aka limit), whereas logarithmic functions start quick but then taper out towards an [x] infinity, bounded by a horizontal asymptote (aka limit).
If we use the natural logarithm (ln) as an example, the constant "e" is the base of ln, such that:
ln(x) = y, which is really stating that the base (assumed "e" even though not shown), that:
[tex] {e}^{y} = x[/tex]
if we try to solve for y in this form it's nearly impossible, that's why we stick with ln(x) = y
but to find the inverse of the form:
[tex]{e}^{y} = x[/tex]
switch the x and y, then solve for y:
[tex] {e}^{x} = y[/tex]
So the exponential function is the inverse of the logarithmic one, f(x) = ln x
If we use the natural logarithm (ln) as an example, the constant "e" is the base of ln, such that:
ln(x) = y, which is really stating that the base (assumed "e" even though not shown), that:
[tex] {e}^{y} = x[/tex]
if we try to solve for y in this form it's nearly impossible, that's why we stick with ln(x) = y
but to find the inverse of the form:
[tex]{e}^{y} = x[/tex]
switch the x and y, then solve for y:
[tex] {e}^{x} = y[/tex]
So the exponential function is the inverse of the logarithmic one, f(x) = ln x
Exponential and logarithmic functions are related in that they are inverses of each other.
Logarithmic functions and exponential functions are inverses of each other.
For instance, let [tex]log a = b[/tex]
In order to eliminate the logarithmic function, we will apply an exponential function ([tex]e[/tex])to both sides.
[tex]e^{loga} = e^b[/tex]
The exponential function will cancel out the logarithmic function since they are inverses of each other to give:
[tex]a = e^b[/tex]
This example shows the inverse relationship that exists between the logarithmic and exponential functions.
Learn more here: https://brainly.com/question/7988782