Respuesta :
Answer is: Only Test 2 will indicate a chemical property of sodium bicarbonate. Tests 1 and 3 will show a physical property of the substance.
Solubility in water and melting point of substance are physical property. In test 2 there is chemical property (chemical reaction):
NaHCO₃ + CH₃COOH → H₂O + CO₂ + CH₃COONa.
Solubility in water and melting point of substance are physical property. In test 2 there is chemical property (chemical reaction):
NaHCO₃ + CH₃COOH → H₂O + CO₂ + CH₃COONa.
Answer:
Only Test 2 will indicate a chemical property of sodium bicarbonate. Tests 1 and 3 will show a physical property of the substance.
Explanation:
1) In test 1 we are dissolving sodium bicarbonate and here there is no chemical change in the property of sodium bicarbonate if it dissolved so it is a pure physical process.
2) In test 2 we are reacting sodium bicarbonate with vinegar (acetic acid).
The reaction is:
[tex]NaHCO_{3}+CH_{3}COOH--->CH_{3}COONa+H_{2}O+CO_{2}[/tex]
Due to formation of carbon dioxide it fizzes. Thus this is a chemical property of sodium bicarbonate to acts as base.
3) In test 3, we are heating and testing the melting point of sodium bicarbonate, which is again a physical property.