Respuesta :
(a) Newton's second law states that the resultant of the forces acting on an object of mass m is equal to the product between the mass m and the acceleration a of the object:
[tex]\sum F = ma[/tex]
In our case, there are two forces acting on the crate: the horizontal force F pushing the object and the friction force [tex]\mu m g[/tex], where [tex]\mu[/tex] is the friction coefficient. The crate is moving at steady speed, so its acceleration is zero: a=0, so Newton's second law becomes
[tex]F-\mu m g=0[/tex]
So, the intensity of the horizontal force is
[tex]F=\mu mg=(0.30)(22 kg)(9.81 m/s^2)=64.7 N[/tex]
(b) If the friction coefficient is zero, it means there is no friction force acting on the crate, so Newton's second law simply becomes
[tex]F=0[/tex]
So, no force is needed to keep the crate at steady speed.
[tex]\sum F = ma[/tex]
In our case, there are two forces acting on the crate: the horizontal force F pushing the object and the friction force [tex]\mu m g[/tex], where [tex]\mu[/tex] is the friction coefficient. The crate is moving at steady speed, so its acceleration is zero: a=0, so Newton's second law becomes
[tex]F-\mu m g=0[/tex]
So, the intensity of the horizontal force is
[tex]F=\mu mg=(0.30)(22 kg)(9.81 m/s^2)=64.7 N[/tex]
(b) If the friction coefficient is zero, it means there is no friction force acting on the crate, so Newton's second law simply becomes
[tex]F=0[/tex]
So, no force is needed to keep the crate at steady speed.
Horizontal force to move the crate at a steady speed across the floor is 64.746 N
There is no horizontal force when coefficient of friction is zero.
Given :
Mass = 22 kg
Coefficient of friction = 0.30
a = 0, because crate moving at a steady speed.
Solution :
Horizontal force to move the crate at a steady speed across the floor is,
F = ma (According to Newton's second law)
[tex]\rm F - \mu mg =0[/tex] (since acceleration is zero)
[tex]\rm F = 0.30\times 22 \times 9.81[/tex]
[tex]\rm F = 64.746\;N[/tex]
Now, when coefficient of friction is zero than friction force is also zero. Therefore horizontal force is,
F = 0
So, there is no horizontal force when coefficient of friction is zero.
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https://brainly.com/question/9450295?referrer=searchResults
