The bulls eye on an archery target has a radius of 3 inches. the entire target has a radius of 9 inches. to the nearest tenth, find the area of the target outside of the bulls eye.

Question

02-04-2018
Mathematics

contestada

The bulls eye on an archery target has a radius of 3 inches. the entire target has a radius of 9 inches. to the nearest tenth, find the area of the target outside of the bulls eye.

Respuesta :

Otras preguntas

A rectangular shaped tank measures 42 1/2 inches in length, 18 inches in width, and 6 1/8 inches in depth. What is the total surface area of this tank

A. Established the first communist government in eastern asia B. Gained military support from japanese military C. Ended chinas participation in the united nati

What are the types of cancer?

Acil cevap❗ A,B,C birer rakam olmak üzere AAxBC=2002 olduğuna göre A+B+C en çok kaç olabilir? Biliyorsanız cevaplayın bilmiyorsanız boşuna yazmayın lütfen

Consider the function f(x) = 2x² - 9x + 1. Step 1 of 2: Interpret the meaning of f(-5) = 96. a. The instantaneous rate of change at x = -5 is 96. b. The slope o

If a child pulls a sled through the snow on a level path with a force of 50 N exerted at an angle of 38 8 above the horizontal, find the horizontal and vertical

The base number can also be a fraction. Convert the decimals to fractions in Examples 7 and 8 and evaluate. Leave your answer as a fraction. Remember how to mul

Answer all questions related to lactose intolerence down below need asap no gibberish Topic Lactose intolerance what is it, rates, why do some develop this , da

bhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh helppppppppppppppppppppppppppppppp

y varies jointly as x and the square of z and inversely as n. if y=80 when x=9, z=4, and n=18, find y when x=32, z=7, and n=35

Аноним Аноним · Answer 1 · 2018-04-02T07:48:32+02:00

Area of a circle = πr²

--------------------------------------------------------
Area of the archery target :
--------------------------------------------------------
Area of the archery target = 9²π

Area of the archery target = 81π

--------------------------------------------------------
Area of the bull's eye :
--------------------------------------------------------
Area of the bull's eye = 3²π

Area of the bull's eye = 9π

--------------------------------------------------------
Area outside the bull's eye :
--------------------------------------------------------
Area of the target outside the bull's eye = 81π - 9π

Area of the target outside the bullseye =72π or 226.19 in²

--------------------------------------------------------
Answer: 226.19 in²
--------------------------------------------------------