Answer:
90 arrangements
Step-by-step explanation:
Since there are no repititions of letters, there are unique 10 letters in total.
THe number of arrangements would be 2 permutation 10. We need the formula for permutation. That is:
[tex]nPr=\frac{n!}{(n-r)!}\\[/tex]
Now, n = 10 [total] and r is 2, so we have:
[tex]nPr=\frac{n!}{(n-r)!}\\\\_{10}P_{2}=\frac{10!}{(10-2)!}\\=\frac{10!}{8!}\\=\frac{10*9*8!}{8!}\\=10*9\\=90[/tex]
So, there can be 90 arrangements
