Respuesta :
Let
x-----------> the distances measured in miles
Abby method
1)2x
2)2x-20%------> 2x-0.4x
algebraic expression-----> [2x-0.4x]---------> 1.6x
Renato method
1)x/5
2)(x/5)*8-------> 8x/5
algebraic expression----->[8x/5]---------------> 1.6x
Part B)
[2x-0.4x]=[8x/5]---------> 1.6x=8x/5--------> 5*(1.6x)=8x-------> 8x=8x
therefore
the two methods give the same answer
the answer is 1.6x
x-----------> the distances measured in miles
Abby method
1)2x
2)2x-20%------> 2x-0.4x
algebraic expression-----> [2x-0.4x]---------> 1.6x
Renato method
1)x/5
2)(x/5)*8-------> 8x/5
algebraic expression----->[8x/5]---------------> 1.6x
Part B)
[2x-0.4x]=[8x/5]---------> 1.6x=8x/5--------> 5*(1.6x)=8x-------> 8x=8x
therefore
the two methods give the same answer
the answer is 1.6x
Answer:
a) Abby's expression
[tex]2x-\frac{20\times 2x}{100}[/tex]
Renato's expression,
[tex]\frac{x}{5}\times 8[/tex]
b) Both methods will give the same answer.
Step-by-step explanation:
a) Let x be the number of miles,
∵ Double of x = 2x,
20% of 2x = [tex]\frac{20\times 2x}{100}[/tex]
Thus, number of kilometers in x miles = 2x - 20% of 2x
= [tex]2x-\frac{20\times 2x}{100}[/tex]
Which is Abby's expression,
Now, Renato's expression of kilometers in x miles = [tex]\frac{x}{5}\times 8[/tex]
[tex]=\frac{8x}{5}[/tex]
b) [tex]\because 2x-\frac{20\times 2x}{100} = \frac{200x-40x}{100}=\frac{160x}{100}=\frac{8x}{5}[/tex]
Hence, two methods will give the same answer.