Respuesta :
Answer: The answer is 20,000 feet squared.
Step-by-step explanation: I don't know how ya'll got that one right but that's not how your supposed to do it. How I am currently getting taught is figuring out the length of the side parallel to the deck.
That equation is 400-2x
Then, you do this to solve for area;
A=L*W (substitute)
A=L(400-2x)
A=x(400-2x)
A=-2x^2 + 400x
Then, to find the x coordinate of the parabola, you do -b/2(a)
This substituted is -400 divided by -4, which equals 100.
So, now we know that x=100. substitute in 100 for x, and we get;
A=-2(100^2) + 400*100
A=-20,000+40,000 which equals...
20,000
The maximum area that can be enclosed by the edging is; 20,000 ft²
What is the Maximum Area?
From the conditions in the question, the width equation can be written as; w = 400 - 2x
where x is length of the rectangle
Thus, the area of rectangle is;
A = L * W
A = x(400 - 2x)
A = -2x² + 400x
To get the x coordinate of the parabola, it is gotten from the formula;
x = -b/2a
plugging in the relevant values gives;
x = -400/(2 * -2)
x = 100
Thus maximum area is;
A_max = -2(100)² + 400(100)
A_max = -20,000 + 40,000
A_max = 20,000 ft²
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