The current is the quantity of charge Q flowing through a certain point of the wire in a time interval of [tex]\Delta t[/tex]:
[tex]I= \frac{Q}{\Delta t} [/tex]
So, by using this relationship and I=1.40 A, we can find the charge passing any point in the wire in 1 second:
[tex]Q=I \Delta t=(1.40 A)(1.0 s)=1.40 C[/tex]
To find how many electrons corresponds to this charge, we should divide this value by the charge of a single electron ([tex]q=1.6 \cdot 10^{-19}C[/tex]):
[tex]N= \frac{Q}{q}= \frac{1.40 C}{1.6 \cdot 10^{-19} C}=8.75 \cdot 10^{18} [/tex] electrons
