The kinetic energy of an object is given by
[tex]K= \frac{1}{2} mv^2[/tex]
where m is the mass of the object and v its velocity.
For the car in the problem, [tex]m=1700 kg[/tex] and [tex]v=30 m/s[/tex], so the kinetic energy of the car is
[tex]K= \frac{1}{2}mv^2= \frac{1}{2}(1700 kg)(30 m/s)^2=7.65\cdot 10^5 J [/tex]
and as we can see, yes, the answer depends on the car's mass.
