Find an equation for a sinusoidal function that has period 360°, amplitude 1, and contains the point (180°,0). Write your answer in the form f(x)=Asin(Bx+C)+D, where A, B, C, and D are real numbers.
The answer is: f(x) = 1*Sin(1*x + k*π). It must be remembered that: 360°= 2π. 180° = π. Therefore we see that: A = 1, where A represents the amplitude. B is equal to (2π / T) and T is the period of oscillation. If B = 1 then T = 2pi = 360 ° as requested. C is the phase. In the required equation C = kπ, where k is any whole number. D = 0 Below is a graph of the equation: f (x) = 1sin (x + kπ) with k = 2 for this case. It can be seen that indeed the equation satisfied all the requirements of the problem
