For this case, the first thing to do is write the equation of moving the ball.
We have then:
h (t) = - 16t ^ 2 + 130t + 2
Deriving we have:
h '(t) = - 32t + 130
We match zero:
-32t + 130 = 0
We cleared t:
t = 130/32
t = 4.0625 s
We evaluate the value of t = 4.0625 s in the equation of motion:
h (4.0625) = - 16 * (4.0625) ^ 2 + 130 * (4.0625) + 2
h (4.0625) = 266.0625 feet
Answer:
The maximum height, in feet, the ball will attain is:
h (4.0625) = 266.0625 feet
