By using Pythagoras theorem, length of one leg of triangle can be determined.
Given:
A triangle with length of one leg and the hypotenuse
According to question,
Let the length of one leg of triangle which can be base [tex](b)[/tex] or perpendicular [tex](p)[/tex] and hypotenuse represented by [tex](h)[/tex].
Now, using Pythagoras theorem which states that if a triangle is right-angled ([tex]90[/tex] degrees), then the square of the hypotenuse is equal to the sum of the squares of the other two sides.
From the figure,
In [tex]\Delta AOB, \;\angle O=90^\circ[/tex]
[tex]\rm{H^2=P^2+B^2}\\\rm{AB^2=AO^2+OB^2[/tex]
[tex]h^2=p^2+b^2[/tex]
[tex]b=\sqrt{h^2-p^2}\\[/tex]
or
[tex]p=\sqrt{h^2-b^2}\\[/tex]
Therefore, length of one leg of the triangle is determined by using Pythagoras theorem.
Learn more about Pythagoras theorem here:
https://brainly.com/question/15138986
