Respuesta :
The correct answer is the first:
The interquartile range of Mitchell's data is greater than the interquartile range of Luke's data.
Since the interquartile range (RIC) is equal to:
RIC = Q3-Q1
Of the gracifa can be observed quer for the case of Mitchell:
RIC = 34-25 = 9
While for Luke's case:
RIC = 36-28 = 8.
Therefore Mitchell's interquartile range (RIC) is greater than Luke's.
The interquartile range of Mitchell's data is greater than the interquartile range of Luke's data.
Since the interquartile range (RIC) is equal to:
RIC = Q3-Q1
Of the gracifa can be observed quer for the case of Mitchell:
RIC = 34-25 = 9
While for Luke's case:
RIC = 36-28 = 8.
Therefore Mitchell's interquartile range (RIC) is greater than Luke's.
Answer:
A. The interquartile range of Mitchell's data is greater than the interquartile range of Luke's data.
Step-by-step explanation: