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which statement is true for log3 (x+1)=2?

x+1= 3^2
x+1=2^3
2(x+1)=3
3(x+1)=2

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thedataco1p821ps thedataco1p821ps · Answer 1 · 2018-05-01T23:20:35+02:00

the first statement should be true

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bhoopendrasisodiya34 bhoopendrasisodiya34 · Answer 2 · 2022-03-11T07:43:18+01:00

The statement which is true for the logarithmic function, log3 (x+1) equal to 2 is similar to option A, which is,

[tex](x+1)=3^2[/tex]

The exponent of the log rule says that the raising a logarithm with a number to its base is equal to the number.

For example,

[tex]\log_b k=x\\[/tex]

It can be written as,

[tex]b_x=k[/tex]

Let k is the number and b is the base thus,

The given logarithmic function in the problem is,

[tex]\log_3 (x+1)=2[/tex]

By the property of exponent of the logarithmic function, the above expression can be written as,

[tex]3^2=(x+1)[/tex]

Rewrite the above equation as,

[tex](x+1)=3^2[/tex]

Hence, the statement which is true for the logarithmic function, log3 (x+1) equal to 2 is similar to option A, which is,

[tex](x+1)=3^2[/tex]

Learn more about the rules of logarithmic function here;

https://brainly.com/question/13473114