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How many liters of chlorine gas, at standard temperature and pressure, will react with 15.5 grams of potassium metal? Show all of the work used to solve this problem.

2K + Cl2 —> 2KCl

Respuesta :

2013345
I think about 6.2 liters

Answer:

V = 6.8 L

Explanation:

2K(s) + Cl2(g) --> 2KCl(s)

25.6g.....?L  

25.6g K x (1 mol K / 39.1g K) x (1 mol Cl2 / 2 mol K) = 0.3274 mol Cl2

PV = nRT

V = nRT / P

V = 0.3274 mol x 0.08206 Latm/molK x 278K / 1.1 atm

V = 6.8 L

The pressure (1.1 atm), which is expressed to two significant digits, limits the precision of the answer to two significant digits.

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