Cross section of a metal ingot is a trapezoid the cross section has an area of 39 square cm the top base of the cross section is 12 CM the length of the bottom base is 2 cm greater than the top base how tall is the Metal Ingot explain

Respuesta :

The area of a trapezoid is given by the formula
  A = (1/2)(b₁ +b₂)×h
Fill in the given information and solve for h.
  39 cm² = (1/2)(12 cm +(12 cm +2 cm))×h
  39 cm²/(13 cm) = h = 3 cm

The height of the metal ingot is 3 cm.