A businessman has 10 employees; his salary is equal to 6 times the average of employees' salary. If the 11 of them received a total of 64000 in a one year, what was the businessman's salary that year?

Respuesta :

Let [tex]x[/tex] be the average salary of an employee. Since the salary of the business man is 6 times the average salary of an employee, his salary will be [tex]6x[/tex]. We also know that the sum of the salary of the businessman and the average salaries of his 10 employees is 640000, so:
[tex]6x+10x=64000[/tex]
Solving for [tex]x[/tex]:
[tex]16x=64000[/tex]
[tex]x= \frac{64000}{16} [/tex]
[tex]x=4000[/tex]
The average salary of an employee is 4000, so the salary of the businessman will be [tex]6*4000=24000[/tex].

We can conclude that the business man's salary that year was 24000.