Respuesta :
C(-4;3)
D(1:0)
Image the right triangle between C, D and the point A(-4,0)
CA is 3-0=3; AD is 1-(-4)=1+4=5
CD is √3²+5²=√34=5.8309...
D(1:0)
Image the right triangle between C, D and the point A(-4,0)
CA is 3-0=3; AD is 1-(-4)=1+4=5
CD is √3²+5²=√34=5.8309...
Answer:
Option C.
Step-by-step explanation:
Coordinates of the points C and D are (-4, 3) and (1, 0)
We have to find the distance CD.
Distance CD = [tex]\sqrt{(x-x')^{2}+(y-y')^{2}}[/tex]
CD = [tex]\sqrt{(1+4)^{2}+(0-3)^{2}}[/tex]
= [tex]\sqrt{25+9}[/tex]
= [tex]\sqrt{34}[/tex]
= 5.83 units
Therefore, Option C. distance CD = 5.83 units is the answer.