Respuesta :
The initial cost of car B is 25,000.
The cost of fuel consumed in n years by car B is
[tex]=n\times \frac{15000\:miles}{year}\times \frac{1\:gallon}{45\:miles}\times \frac{4\:dollars}{gallon}[/tex]
Equate the initial cost to the cost of fuel
[tex]25000=n\times \frac{15000\:miles}{year}\times \frac{1\:gallon}{45\:miles}\times \frac{4\:dollars}{gallon}[/tex]
[tex]25000=\frac{4000n}{3}[/tex]
[tex]n=\frac{25000\left(3\right)}{4000}[/tex]
[tex]n=18.75[/tex]
It will take 18.75 years for Car B's better fuel economy to outweigh its higher initial cost.
The cost of fuel consumed in n years by car B is
[tex]=n\times \frac{15000\:miles}{year}\times \frac{1\:gallon}{45\:miles}\times \frac{4\:dollars}{gallon}[/tex]
Equate the initial cost to the cost of fuel
[tex]25000=n\times \frac{15000\:miles}{year}\times \frac{1\:gallon}{45\:miles}\times \frac{4\:dollars}{gallon}[/tex]
[tex]25000=\frac{4000n}{3}[/tex]
[tex]n=\frac{25000\left(3\right)}{4000}[/tex]
[tex]n=18.75[/tex]
It will take 18.75 years for Car B's better fuel economy to outweigh its higher initial cost.
Answer: The answer is B) 11.25
Step-by-step explanation: I got it right