Respuesta :
Answer:
15, -26
Step-by-step explanation:
The generic solution to a "sum and difference" problem can be found easily. Let "a" and "b" represent the numbers you seek, and let "s" and "d" represent their sum and difference:
a + b = s
a - b = d
Adding these two equations tells you ...
2a = s + d
a = (s + d)/2 . . . . . . divide by the coefficient of a
You can find "b" several different ways. One way is to subtract the second equation from the first:
2b = s - d
b = (s - d)/2 . . . . . . divide by the coefficient of b
So, the second number can be found from any of ...
- b = s - a
- b = a - d
- b = (s - d)/2
____
For the numbers given here, s=-11, d=41, the two numbers are ...
a = (-11 +41)/2 = 15
b = -11 -15 = -26
The two numbers are 15 and -26.
Answer:
15, -26
Step-by-step explanation:
The generic solution to a "sum and difference" problem can be found easily. Let "a" and "b" represent the numbers you seek, and let "s" and "d" represent their sum and difference:
a + b = s
a - b = d
Adding these two equations tells you ...
2a = s + d
a = (s + d)/2 . . . . . . divide by the coefficient of a
You can find "b" several different ways. One way is to subtract the second equation from the first:
2b = s - d
b = (s - d)/2 . . . . . . divide by the coefficient of b
So, the second number can be found from any of ...
b = s - a
b = a - d
b = (s - d)/2
____
For the numbers given here, s=-11, d=41, the two numbers are ...
a = (-11 +41)/2 = 15
b = -11 -15 = -26
The two numbers are 15 and -26.
