How many grams of calcium chloride are needed to produce 1.50 g of potassium chloride? cacl2(aq) + k2co3(aq) → 2 kcl(aq) + caco3(aq) 1.12 g 2.23 g 0.896 g 4.47 g?

Stoichiometry in Chemistry learn about chemicals mainly emphasizes quantitative, such as the calculation of volume, mass, number, which is related to numbers, molecules, elements, etc.

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.

In the reaction there are also manifestations of reagent substances namely gas (g), liquid (liquid / l), solid (solid / s) and solution (aqueous / aq).

Reactions that occur:

CaCl₂ (aq) + K₂CO₃ (aq) → 2 KCl (aq) + CaCO₃ (aq)

From the reaction equation above, the reaction coefficient shows the mole ratio of reagents and products

mol CaCl₂: moles of KCl = 1: 2

relative molecular mass KCl = 74.6

relative molecular mass of CaCl2 = 111

then the mole:

mole KCl = mass: relative molecular mass

mole KCl = 1.5 gram: 74.6

mole KCl = 0.020107

so that

mole CaCl₂ = 1/2. 0.020107

mole CaCl₂ = 0.0100535

So the mass of CaCl2 = mole x relative molecular mass

mass CaCl₂ = 0.0100535 x 111

mass CaCl₂ = 1.12 gram

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Keywords: CaCl2, KCl, mole, mass, relative molecular mass

Eduard22sly Eduard22sly · Answer 2 · 2021-10-01T19:42:33+02:00

The mass calcium chloride needed is 1.12 g

The balanced equation for the reaction is illustrated below:

CaCl₂ + K₂CO₃ —> 2KCl + CaCO₃

Next, we shall determine the mass of CaCl₂ that reacted and the mass of KCl produced from the balanced equation.

Molar mass of CaCl₂ = 40 + (35.5×2)

= 40 + 71

= 111 g/mol

Mass of CaCl₂ from the balanced equation = 1 × 111 = 111 g

Molar mass of KCl = 39 + 35.5

= 74.5 g/mol

Mass of KCl from the balanced equation = 2 × 74.5 = 149 g

Thus,

From the balanced equation above,

111 g of CaCl₂ reacted to produce 149 g of KCl.

Finally, we shall determine the mass of CaCl₂ needed to produce 1.5 g of KCl as follow:

From the balanced equation above,

111 g of CaCl₂ reacted to produce 149 g of KCl.

Therefore, X g of CaCl₂ will react to produce 1.5 g of KCl i.e

X g of CaCl₂ = [tex]\frac{1.5 * 111}{149}[/tex]

X g of CaCl₂ = 1.12 g

Thus, 1.12 g of calcium chloride, CaCl₂ is needed to produce 1.5 g of KCl.

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