Respuesta :

Because there are  g(x)=√(x-1) +1 have  √ and +1, the values of g(x) can be only positive.
Value under √ should be positive.
x-1≥0
x≥1.

Correct answer is A.

Answer:

First graph

Step-by-step explanation:

Given function,

[tex]g(x)=\sqrt{x-1}+1[/tex]

∵ The point from which the graph of the function passes through will be satisfy the function,

In the first graph,

Graph is passing through (1, 1), (5, 3) and (10, 4),

[tex]1=\sqrt{1-1}+1[/tex]

[tex]3=\sqrt{5-1}+1[/tex]

[tex]4=\sqrt{10-1}+1[/tex]

So, all points (1, 1), (5, 3) and (10, 4) satisfy the function,

In the second graph,

Graph is passing through (-1, -1), (3,1) and (8,2),

Since,

[tex]-1\neq \sqrt{-1-1}+1[/tex]

So, all points of graph 2 do not satisfy the function,

In the third graph,

Graph is passing through (1, -1), (5, 1) and (10, 2),

[tex]-1\neq \sqrt{1-1}+1[/tex]

So, all points of graph 3 do not satisfy the function,

In the fourth graph,

Graph is passing through (-1, 1), (3, 3) and (8, 4),

[tex]1\neq \sqrt{-1-1}+1[/tex]

So, all points of graph 4 do not satisfy the function

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