Respuesta :
For this case we can use the law of cosine to determine the length of side b.
We have then:
b ^ 2 = a ^ 2 + c ^ 2 - 2 * a * c * cos (B)
Substituting values we have:
b ^ 2 = 4 ^ 2 + 5 ^ 2 - 2 * 4 * 5 * cos (60)
Clearing b:
b = root (4 ^ 2 + 5 ^ 2 - 2 * 4 * 5 * cos (60))
Answer:
an expression that is equivalent to the length of side b is:
b = root (4 ^ 2 + 5 ^ 2 - 2 * 4 * 5 * cos (60))
We have then:
b ^ 2 = a ^ 2 + c ^ 2 - 2 * a * c * cos (B)
Substituting values we have:
b ^ 2 = 4 ^ 2 + 5 ^ 2 - 2 * 4 * 5 * cos (60)
Clearing b:
b = root (4 ^ 2 + 5 ^ 2 - 2 * 4 * 5 * cos (60))
Answer:
an expression that is equivalent to the length of side b is:
b = root (4 ^ 2 + 5 ^ 2 - 2 * 4 * 5 * cos (60))
Answer:
[tex]b=\sqrt{25+16-20}[/tex]
Step-by-step explanation:
(The choices are attached)
We don't if the triangle ABC is a right triangle of other kind, that's why we need to use the cosines law which is defined as
[tex]b^{2}=a^{2} +c^{2}-2.a.c.cosB\°[/tex]
Where [tex]a=4[/tex] [tex]c=5[/tex] and [tex]B=60\°[/tex], replacing these values we have
[tex]b^{2}=4^{2}+5^{2}-2(4)(5)cos(60\°)\\ b=\sqrt{16+25-40\frac{1}{2} }\\ b=\sqrt{25+16-20}[/tex]
Remember that [tex]cos60\°=\frac{1}{2}[/tex]
Therefore, the second choice is the correct answer
[tex]b=\sqrt{25+16-20}[/tex]