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The electric field between two parallel plates has a magnitude of 875 N/C. The positive plate is .002 m away from the negative plate. What is the electric potential difference between the plates?

Respuesta :

djmegafreeze
Given:
E = 875 N/C electric field
d = 00.002 m, distance between parallel plates

Note that
1 V = 1 J/C

The electric potential difference is


Answer: 1.8 V (nearest tenth)

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