Respuesta :
To solve this problem you must apply the proccedure shown below:
1. You have the following information given in the problem above:
- The spherical bubble gum ball is at the bottom
- The radius of the cone is 1.5 inches, and its height is 3 inches.
- The diameter of the bubble gum ball is 0.5 inches.
2. Therefore, you must apply the formula for calculate the volume of a sphere to find the volume of the bubble gum ball:
Vs=4πr^3/3
r is the radius (r=0.5 inches/2=0.25 inches)
Vs=4π(0.25 inches)^3/3
Vs=0.065 inches^3
3. The volume of the cone is:
Vc=πr^2h/3
r is the radius of the cone (r=1.5 inches)
h is the height (h= 3 inches)
Vc=π(1.5 inches)^2(3 inches)/3
Vc=7.06 inches^3
What is the closest approximation of the volume of the cone that can be filled with flavored ice?
Vt=Vc-Vs
Vt≈7.00 inches^3
1. You have the following information given in the problem above:
- The spherical bubble gum ball is at the bottom
- The radius of the cone is 1.5 inches, and its height is 3 inches.
- The diameter of the bubble gum ball is 0.5 inches.
2. Therefore, you must apply the formula for calculate the volume of a sphere to find the volume of the bubble gum ball:
Vs=4πr^3/3
r is the radius (r=0.5 inches/2=0.25 inches)
Vs=4π(0.25 inches)^3/3
Vs=0.065 inches^3
3. The volume of the cone is:
Vc=πr^2h/3
r is the radius of the cone (r=1.5 inches)
h is the height (h= 3 inches)
Vc=π(1.5 inches)^2(3 inches)/3
Vc=7.06 inches^3
What is the closest approximation of the volume of the cone that can be filled with flavored ice?
Vt=Vc-Vs
Vt≈7.00 inches^3