Answer:
C, E, F
Step-by-step explanation:
The range of the function [tex]g(x)=x^2[/tex] is [tex]y\in [0,\infty)[/tex], the range of the function [tex]h(x)=-x^2[/tex] is [tex](-\infty,0][/tex]
This means that for any value of x, the value of [tex]g(x)[/tex] is always greater or equal to the value of [tex]h(x)[/tex] (the values are equal at x=0).
So, options A and B are false, because at x=0 the values are equal and h(x) cannot be greater than g(x)
Options C, E and F are true, because for all non-zero x, g(x)>h(x).
Option D is false (the reason is the same as for option B)