Answer:
NO
YES
NO
NO
Step-by-step explanation:
For a number to be the solution of the equation, the number should satisfy it.
To check if t satisfies, plug the number and compare LHS and RHS.
1) 3z + 4 = 15
Substituting z = -5, we get 3(-5) + 4 = -15 + 4 = -11 [tex]$ \ne $[/tex] 15.
Therefore, -5 is not the solution of the equation.
2) 8 - [tex]$ \frac{x}{2} $[/tex] = 0
Substituting x = 16, we get 8 - [tex]$ \frac{16}{2} = 8$[/tex]
⇒ 8 - 8 = 0
Therefore, 16 is a solution of the equation.
3) 4(p + 5) = 60
Substitute p = 12. 4(12 + 5) = 4(17) [tex]$ \ne $[/tex] 60.
Not a solution.
4) 8 - k = -48
If k = -40, then 8 - (-40) = 48
On the RHS we have -48. Not equal. So, it is not a solution.
