Find the​ (a) mean,​ (b) median,​ (c) mode, and​ (d) midrange for the data and then​ (e) answer the given question.

Listed below are the jersey numbers of 11 players randomly selected from the roster of a championship sports team. What do the results tell​ us?

60    
31
19    
55    
21    
37    
94    
62    
41    
15    
34

(a) Find the mean.
(b) Find the median.

Respuesta :

Answer:

(a) Mean = 42.64

(b) Median= 37

(d)Midrange =39

Step-by-step explanation:

Given data,

60,31,19,55,21,37,94,62,41,15,34

(a)

Mean: Mean is the ratio of all observation to the total number of observation.

[tex]Mean=\frac{\textrn{sum of all observation}}{\textrm{Total number of observation}}[/tex]

         [tex]=\frac{60+31+19+55+21+37+94+62+41+15+34}{11}[/tex]

        =42.64

(b)

To find the mean of given data,first we have to arrange the date in ascending order or descending order.

Median: Median is middle term of the observation.

15,19,21,31,34,37,41,55,60,62,94

[tex]Median =(\frac{n+1}{2})^{th} term[/tex]     n = Total number of observation=11

              [tex]=(\frac{11+1}{2})^{th}term[/tex]

              = 6th term

              =37

(c)

Mode is a observation which repeat maximum time.

Here all observations have only one one frequency, so it is multimodel data.

(d)

Midrange: The substraction of first quartile from third quartile.

First quartile: The mid-value of lower half.

Lower portion :15,19,21,31,34

[tex]Q_1=21[/tex]

Third quartile: The middle value of upper half.

upper half: 41,55,60,62,94

[tex]Q_3= 60[/tex]

Mid range = [tex]Q_3-Q_1[/tex]

                 =60-21

                 =39