Respuesta :
Answer:
(a) Mean = 42.64
(b) Median= 37
(d)Midrange =39
Step-by-step explanation:
Given data,
60,31,19,55,21,37,94,62,41,15,34
(a)
Mean: Mean is the ratio of all observation to the total number of observation.
[tex]Mean=\frac{\textrn{sum of all observation}}{\textrm{Total number of observation}}[/tex]
[tex]=\frac{60+31+19+55+21+37+94+62+41+15+34}{11}[/tex]
=42.64
(b)
To find the mean of given data,first we have to arrange the date in ascending order or descending order.
Median: Median is middle term of the observation.
15,19,21,31,34,37,41,55,60,62,94
[tex]Median =(\frac{n+1}{2})^{th} term[/tex] n = Total number of observation=11
[tex]=(\frac{11+1}{2})^{th}term[/tex]
= 6th term
=37
(c)
Mode is a observation which repeat maximum time.
Here all observations have only one one frequency, so it is multimodel data.
(d)
Midrange: The substraction of first quartile from third quartile.
First quartile: The mid-value of lower half.
Lower portion :15,19,21,31,34
[tex]Q_1=21[/tex]
Third quartile: The middle value of upper half.
upper half: 41,55,60,62,94
[tex]Q_3= 60[/tex]
Mid range = [tex]Q_3-Q_1[/tex]
=60-21
=39