The area of a regular octagon with an apothem of 2 cm is 3cm ^2.
The area of a regular octagon with an apothem of 2 cm.
Given the apothem length,
the area of a regular polygon becomes,
[tex]A=\frac{1}{2}\times P\times A[/tex]
P= the perimeter of the regular polygon
A is the apothem of the regular polygon
Here, we get
p=2=2cm, a=3cm.
So, plugging in the given values, we get
[tex]A=\frac{1}{2} \times 2cm\times 3cm[/tex]
A=1cm⋅3cm
A=3cm^2
Therefore the area of a regular octagon with an apothem of 2 cm is 3cm ^2.
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